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Please help jandfjbnsjdfnbsd

Please help jandfjbnsjdfnbsd-example-1

2 Answers

1 vote
ax^{2}+bx+c
to factor, find numbers that add up to b but multiply to c. these would by 3 and 2

(x+2)(x+3), so D would be a factor
answered
User WorkaroundNewbie
by
8.7k points
1 vote
x² + 5x + 6
x 3
x 2

(x+3)(x+2)

to find this, you must get two numbers (or variables) that will give you the number on the top when multiplied, while giving you the number in the middle when added together.
To prove this, do the FOIL method when you are solve the binomials & make it into a trinomial

x(x) = x^2
x(3) = 3x
x(2) = 2x
3(2) = 6
x^2 + 3x + 2x + 6
x^2 + 5x + 6 (simplify numbers with similar variables)

(x+3) is your answer (in this case, since it does not ask you to choose both, and (x+2) is not a choice

hope this helps
answered
User Mike Demenok
by
8.3k points

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