Question

a stone is dropped from a bridge and hits the pavement below in 2 seconds. what is the velocity of the stone when it hits the pavement

Answer 1

Velocity of the stone just before it hits the pavement can be found by using kinematic equation v = u + at.
u = initial velocity = 0 m/s. a = 9.8 m/s^2 . t = 2 sec.
Plug given values to find v.

Answer 2

well gravity is 9.8m/s so i would assume 19.6m/2 is the velocity