Question

What is the f of x over the g of x when f(x) = 6x3 − 19x2 + 16x − 4 and g(x) = x − 2? (2 points)

Answer 1

Answer: A. 6x^2 − 7x + 2

What is the f of x over the g of x when f(x) = 6x^3 − 19x^2 + 16x − 4 and g(x) = x − 2?

A. 6x^2 − 7x + 2

B. 3x^2 − 9x + 8

C. 6x^2 − 7x + 2 − 8/(x-2)

D. 3x^2 − 9x + 8 − 8/(x-2)

Step-by-step explanation:

I just did the assignment and the correct answer is A. 6x^2 − 7x + 2! Hope this helps.

Good Luck!!

Answer 2

You're being asked to divide 6x^3 - 19x^2 + 16x - 4 by x - 2.

Try using synthetic division, if you know it:

_______________
2 / 6 -19 16 -4
12 -14 4
--------------------------
6 -7 2 0

6, -7 and 2 are the coefficients of the quotient. The quotient (answer to this question) is

6x^2 - 7x + 2