Question

What equation is graphed in this figure?

A. y−4=−13(x+2)
B. y−3=13(x+1)
C. y+2=−3(x−1)
D. y−5=3(x−1

Answer 1

Its D I took the quiz

Answer 2

C. y+2=−3(x−1)

Explanation:

To know what is the equation graphed in the figure you should give values to x on the interval (-1,2) and solve for y.

Finally you should compare the obtained values with the graph. Note that you have the following points on the graph: (-1,4); (0,1); (1,2); (2,-5).

1. When x=-1

`A. y-4=-13(x+2)\\\\y-4=-13(-1+2)\\\\y-4=-13(1)\\\\y-4=-13\\\\y=-13+4\\\\y=-9`

(-1,9)

`B. y-3=13(x+1)\\\\y-3=13(-1+1)\\\\y-3=13(0)\\\\y-3=0\\\\y=3`

(-1,3)

`C. y+2=-3(x-1)\\\\y+2=-3(-1-1)\\\\y+2=-3(-2)\\\\y+2=6\\\\y=6-2\\\\y=4`

(-1,4)

`D. y-5=3(-1-1)\\\\y-5=3(-2)\\\\y-5=-6\\\\y=-6+5\\\\y=-1`

(-1,-1)

2. When x=0

`A. y-4=-13(x+2)\\\\y-4=-13(0+2)\\\\y-4=-13(2)\\\\y-4=-26\\\\y=-26+4\\\\y=-22`

(0,22)

`B. y-3=13(x+1)\\\\y-3=13(0+1)\\\\y-3=13(1)\\\\y-3=13\\\\y=13+3\\\\y=16`

(0,16)

`C. y+2=-3(x-1)\\\\y+2=-3(0-1)\\\\y+2=-3(-1)\\\\y+2=3\\\\y=3-2\\\\y=1`

(0,1)

`D. y-5=3(x-1)\\\\y-5=3(0-1)\\\\y-5=3(-1)\\\\y-5=-3\\\\y=-3+5\\\\y=2`

(0,2)

The equation C. y+2=−3(x−1) give the solution points (-1,4), and (0,1), therefore this equation is graphed in the figure.