Question

What is the constant of the expression x-3+2/3-y/2

Answer 1

`-(7)/(3)` is the constant term.

Explanation:

The given expression is
`x-3+(2)/(3)-(y)/(2)`.

We have to find the constant term of the expression.

There are 2 variables given as x and y.

We further solve the expression

`x-3+(2)/(3)-(y)/(2)` =
`x-(y)/(2)-3+(2)/(3)`

=
`x-(y)/(2)+((2-9))/(3)`

=
`x-(y)/(2)-((7))/(3)`

In the given trinomial last term
`-(7)/(3)` is the constant term.