Calculate the number of molecules in 4.56-g of lead (ii) nitrite

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asked Sep 11, 2018 73.2k views

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Garnet · Answer 1 · 2018-09-17T12:43:09+0000

Molar mass of Lead Nitrate, Pb(NO3)2, is 331.2 g/mol. I. e. 201 + 14.007 + (16*3)*2 = 331.2. Number of moles of any compound is just mass/ molar mass; hence we have 4.59/331.2 = 0.0138 g/mol.

Calculate the number of molecules in 4.56-g of lead (ii) nitrite

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