Question

4. What is the perimeter of the regular octagon below? Round
to the nearest hundredth.

Answer 1

Answer: 28.84 units

Step-by-step explanation:

Let's use the distance formula to find the distance from A to B (aka the length of side AB).

`d = √((x_1 - x_2)^2 + (y_1 - y_2)^2)\\\\ d = √((-4-(-1))^2 + (1-(-1))^2)\\\\ d = √((-4+1)^2 + (1+1)^2)\\\\ d = √((-3)^2 + (2)^2)\\\\ d = √(9 + 4)\\\\ d = √(13)\\\\ d \approx 3.60555128\\\\ d \approx 3.6056`

Side AB is roughly 3.6056 units long.

In any regular polygon, the sides are the same length.

Because of that, this regular octagon has 8 sides of roughly 3.6056 units each.

The perimeter is 8*3.6056 = 28.8448 approximately. This rounds to 28.84 when rounding to the nearest hundredth (aka 2 decimal places).