How many moles of nitrogen N are in 71.0g of nitrous oxide , N2O

Question

asked Dec 18, 2018 101k views

2 Answers

Eir Nym · Answer 1 · 2018-12-24T11:41:13+0000

Answer : The number of moles of nitrogen present in nitrous oxide are 3.22 moles.

Explanation : Given,

Mass of
N_2O = 71.0 g

Molar mass of
N_2O = 44 g/mole

First we have to calculate the moles of
.

$\text{ Moles of }N_2O=\frac{\text{ Mass of }N_2O}{\text{ Molar mass of }N_2O}=(71.0g)/(44g/mole)=1.61moles$

Now we have to calculate the moles of nitrogen in nitrous oxide.

In nitrous oxide
N_2O , there are 2 moles of nitrogen and 1 mole of oxygen.

As, 1 moles of
N_2O contains 2 moles of nitrogen

So, 1.61 moles of
N_2O contains
1.61* 2=3.22moles of nitrogen

Therefore, the number of moles of nitrogen present in nitrous oxide are 3.22 moles.