Question

Nine actors audition for four different parts in a play. in how many ways can the director fill these roles?

A:368,880
B:15,120
C:3024
D:126

Answer 1

126 Is your answer

Answer 2

To solve this, we need to find the total number of combinations that can be made from 9 actors and 4 different plays. The formula for combination is:

C = n! / (n – r)! r!

where n = 9, r = 4

C = 9! / (9 – 4)! 4!

C = 126

Answer:

D. 126