asked 194k views
2 votes
Find the work done by the force field f(x,y,z)=2xi+2yj+4k on a particle that moves along the helix r(t)=2cos(t)i+2sin(t)j+5tk,0≤t≤2π.

1 Answer

6 votes

\displaystyle\int_(\mathcal C)\mathbf f\cdot\mathrm d\mathbf r=\int_(t=0)^(t=2\pi)(4\cos t\,\mathbf i+4\sin t\,\mathbf j+20t\,\mathbf k)\cdot(-2\sin t\,\mathbf i+2\cos t\,\mathbf j+5\,\mathbf k)\,\mathrm dt

=\displaystyle\int_(t=0)^(t=2\pi)100t\,\mathrm dt=200\pi^2
answered
User Tim Molendijk
by
8.3k points
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