mâ EFH = 2y+2 I am going to assume that line segment EF is outside of angle GFI and that angle EFG includes angle GFI. That's the only assumption that makes sense given the problem. But I wouldn't have to make that assumption if the diagram was actually included. Since FH bisected GFI, that means that angle HFI is equal to angle HFG. And since angle EFG is actually the sum of angle EFH and angle HFG, all we need to do is subtract HFG from EFG to get EFH. So 4y + 8 - (2y + 6) = 4y + 8 - 2y - 6 = 2y + 2