In a game, you have a 1/36 probability of winning $85 and a 35/36 probability of losing $4. What is your expected value?

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asked Feb 23, 2018 59.2k views

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Edward Romero · Answer 1 · 2018-02-28T16:05:51+0000

In 36 games you would win 1 and lose 35, so the total of all outcomes is 85-4×35=85-140=-55.
The expected value is the mean of these=-55/36=a loss of $1.53.

In a game, you have a 1/36 probability of winning $85 and a 35/36 probability of losing $4. What is your expected value?

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