Question

A basketball player’s free throw percentage is 70%. She has just been awarded 3 free throws after getting fouled on a 3-point shot. Which table shows the correct probability distribution for the possible numbers of free throws made?

Answer 1

.34

Explanation:

Answer 2

P(3 Free Throws) = P(One Free Throw & One Free Throw & One Free Throw)


P(3 Free Throws) = P(One Free Throw) x P(One Free Throw) x P(One Free Throw)


P(3 Free Throws) = (7/10) x (7/10) x (7/10)


P(3 Free Throws) = (7x7x7)/(10x10x10)


P(3 Free Throws) = 343/1000

P(3 Free Throws) = 0.343


The probability is 0.343 to make all 3 free throws.