What is the remainder when the polynomial 8x^2+4x−3 is divided by 2x−1?

Question

asked Feb 18, 2018 73.3k views

2 Answers

PtQa · Answer 1 · 2018-02-22T09:02:42+0000

Answer:

1

Explanation:

Given: A polynomial
8x^(2) +4x-3 is divided by another polynomial
2x-1

To find: Remainder when
8x^(2) +4x-3 is divided by
2x-1

Solution:

To find the remainder when
8x^(2) +4x-3 is divided by
2x-1

First, equate
2x-1 with 0.

Now,
2x-1=0

$\implies2x=1$

$\implies x=(1)/(2)$

Now, to find the remainder put
x=(1)/(2) in
8x^(2) +4x-3

So, we have

8*((1)/(2))^(2)+4((1)/(2) )-3

=8*(1)/(4) +2-3

=2+2-3

=4-3

Hence, the remainder is 1.