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What is the equation of the line that passes through (6, 5) and is perpendicular to 3x−y=7 ?

What is the equation of the line that passes through (6, 5) and is perpendicular to 3x−y=7 ?
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What is the equation of the line that passes through (6, 5) and is perpendicular to 3x−y=7 ?

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User Doug Voss
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So it be -y=-3x+7, then y= 3/1x+7
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User Binbin
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