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-1/3 |h|^2- 2/3 y^3 -2/3 〖|b|〗^3

b = - 1/2 h = 1 1/2 y = -2

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asked
User Ziima
by
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1 Answer

4 votes

-(1)/(3)\left|1\cdot \left((1)/(2)\right)^2\right|-(2)/(3)-2^3-(2)/(3)\left|-(1)/(2)\right|^3

(1)/(3)\left|1\cdot \left((1)/(2)\right)^2\right|=(1)/(12)

(2)/(3)\left|-(1)/(2)\right|^3=(1)/(12)

=-(1)/(12)-(2)/(3)-2^3-(1)/(12)

=-(53)/(6)
answered
User CJ Cullen
by
7.8k points
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