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Find the vertex and the axis of symmetry of the graph of f(x)=3(x+1)^2

1 Answer

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general form of vertex of a parabola is

y = a(x - b)^2 + c where vertex = (b , c)


for this equation the vertex is at (-1,0).

the axis of symmetry is x = -1
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User Dafydd Williams
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