Question

Sandy can jog 3 2/5 miles in 5/6 hour. Find her average speed in miles per hour.

Answer 1

3 2/5 = 17/5

(17/5 mi)/(5/6 hr) = 102/25 mi/hr

Answer 2

`4(2)/(25)` miles per hour

Explanation:

Sandy can jog a distance
`3(2)/(5)` miles or
`(17)/(5)` in the duration =
`(5)/(6)` hours

Since speed =
`(distance)/(time)`

We plug in the values of distance and time in the formula of speed.

Speed =
`((17)/(5))/((5)/(6))`

=
`(17)/(5)` ×
`(6)/(5)`

=
`(102)/(25)`

=
`4(2)/(25)` miles per hour

Her average speed is
`4(2)/(25)` miles per hour.