Question

Find three consecutive even integers such that the sum of twice the smallest number and three times the largest is 42.

Answer 1

let x be the first
the second x +2
the third x+ 4


twice the smallest 2x

three times the largest 3(x+4 )

2x + 3(x+4 )=42

2x +3x +12 = 42

5x= 30

x=6 the second is 8 the third is 10