The sum of 5 consecutive integers is 265

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asked Apr 5, 2018 112k views

1 Answer

Luis Kleinwort · Answer 1 · 2018-04-11T10:07:23+0000

suppose the first one is n, the second is then n+1, the third is n+2, ....
n+(n+1)+(n+2)+(n+3)+(n+4)=265
5n+10=265
5n=255
n=51
so the 5 consecutive integers are: 51,52,53,54,55

The sum of 5 consecutive integers is 265

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