What are the solutions of the equation x^4+3x^2+2=0? Use u substitution to solve.

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asked Dec 25, 2018 145k views

2 Answers

Skyyy · Answer 1 · 2018-12-27T18:43:48+0000

Let u=x^2
so the original equation becomes u^2+3u+2=0
factor: (u+1)(u+2)=0
u=-1 or u=-2
which means x^=-1, or x^2=-2
Since a number squared is never a negative number, there are no real solutions.

What are the solutions of the equation x^4+3x^2+2=0? Use u substitution to solve.

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