Question

−p(d+z)=−2z+59. solve for z.

Answer 1

we have

`-p(d+z)=-2z+59`

Solve for z

`-p(d+z)=-2z+59\\-pd-pz=-2z+59`

Group terms that contain the variable z, and move the other terms to the opposite side of the equation

`-pz+2z=59+pd\\z(2-p)=59+pd`

Divide by
`(2-p)` both sides

`z=((59+pd))/((2-p))`

therefore

the answer is

`z=((59+pd))/((2-p))`