\frac{1 - sin {}^(2)x }{cos {}^(2)x - 1 } = - \cot {}^(2) x

Question

`\frac{1 - sin {}^(2)x }{cos {}^(2)x - 1 } = - \cot {}^(2) x`

Answer 1

`(1-\sin^2x)/(\cos^2x-1)=(\cos^2x)/(-\sin^2x)=-\cot^2x`