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Factor a 2 bc + ab 2 c + abc 2 A. a2b2c2(a + b + c) B. a2bc(a + b + c) C..abc(a + b + c)

Factor a 2 bc + ab 2 c + abc 2 A. a2b2c2(a + b + c) B. a2bc(a + b + c) C..abc(a + b + c)
asked 21.2k views
1 vote
Factor a 2 bc + ab 2 c + abc 2

A. a2b2c2(a + b + c)

B. a2bc(a + b + c)

C..abc(a + b + c)

asked
User Supreeth Meka
by
8.1k points

2 Answers

3 votes

Answer:

abc(a + b + c)

That's your answer!!!

answered
User Dipanshu Chaubey
by
8.1k points
7 votes
a²bc + ab²c + abc²
by assessing the expression, 'abc' can be equally factorised from each term

when abc is factored from each term in the equation then the result would yield

abc(a + b + c) [OPTION C]
answered
User Sven Schoenung
by
8.1k points
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