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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = -2/5(x – 10). What is the standard form of the equation for this line? A)2x…

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = -2/5(x – 10). What is the standard form of the equation for this line? A)2x…
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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = -2/5(x – 10). What is the standard form of the equation for this line? A)2x – 5y = –15 B)2x – 5y = –17 C)2x + 5y = –15 D)2x + 5y = –17

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User IFanie
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7.8k points

1 Answer

3 votes
C.

2x + 5y = - 15
answered
User Mostafa Jamareh
by
8.3k points
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