Question

the sum of three integers is 92. the second number is three times the first number. the third number is ten less than twice the first number. find the integers

Answer 1

1st number = x

2nd number = 3x

3rd number = 2x-10

x +3x + 2x-10 =92

6x - 10 = 92

6x =102

x = 102/6

x = 17

1st number = 17

2nd number = 17*3 = 51

3rd number = 17 *2 = 34-10 = 24

17 + 51 + 24 = 92

3 numbers are 17, 51 and 24