Question

PLEASE HELP ME!!!! WORTH 10 POINTS!!

Write the point-slope form of the given line that passes through the points (-4, -1) and (3, -3). Identify (x1, y1) as (-4, -1).Include your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

Answer 1

(-4, -1) and (3, -3)

slope m = (-3 + 1) /(3 + 4) = -2/7

y - y1 = m(x - x1)
(x1, y1) as (-4, -1)

equation
y + 1 = -2/7(x +4)

Answer 2

`y-(-1)=-(2)/(7)(x-(-4))`

Explanation:

We know that the line passes through (-4,-1) and (3,-3), where
`(x_(1) ,y_(1) )` is
`(-4,-1)` and
`(x_(2) ,y_(2) )` is
`(3,-3)`.

First, we need to find the slope with the formula

`m=(y_(2)-y_(1) )/(x_(2)-x_(1) )`

Replacing given points

`m=(-3-(-1))/(3-(-4))=(-3+1)/(3+4)=(-2)/(7)`

Then, we use the slope, one point and the slope-point form

`y-y_(1) =m(x-x_(1) )\\y-(-1)=-(2)/(7)(x-(-4))\\ y+1=-(2)/(7)x+(8)/(7) \\y=-(2)/(7)x+(8)/(7)-1\\y=-(2)/(7)x+(8-7)/(7) \\y=-(2)/(7)x+(1)/(7)`

The slope-intercept form is

`y=-(2)/(7)x+(1)/(7)`

The point-slope form is

`y-(-1)=-(2)/(7)(x-(-4))`