Register

What is the vertex of the function x^2-6x+8=0 ?

What is the vertex of the function x^2-6x+8=0 ?
asked 208k views
3 votes
What is the vertex of the function x^2-6x+8=0 ?

asked
User Vladislavs Dovgalecs
by
8.9k points

1 Answer

4 votes
-6 / 2 = -3 so
x^2 - 6x + 8 is
(x - 3)^2 -9 + 8

= (x - 3)^2 - 1


the vertex is at (3,-1)
answered
User Maulik Suchak
by
7.8k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!