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For the curve y = ln(x 2 − 3), find the equation of the tangent line at (2, 0).

For the curve y = ln(x 2 − 3), find the equation of the tangent line at (2, 0).
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4 votes
For the curve y = ln(x 2 − 3), find the equation of the tangent line at (2, 0).

asked
User DDDD
by
7.8k points

1 Answer

5 votes
y' = 2x/(x^2 -3) y'(2) = 4
Using the point slope equation:
y-0 = 4(x-2)
y = 4x - 8
answered
User GPack
by
8.7k points
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