Question

The coordinates of quadrilateral EFGH are E(4, 8), F(1, 2), G(6, 1), and H(8, 8). The image of EFGH under dilation is E'F'G'H'.

If the coordinates of vertex E' are (1, 2), what are the coordinates of vertex H'?
No pic is attached

A)  (2, 8)


B) (5, 6)
C) (2, 2)
D)  (4, 8)

Answer 1

the answer is (2,2) because the dilation is by 1/4 

Answer 2

E goes from (4,8) to (1,2) which equals a 1/4 scale factor ( put lower number over higher number so X = 1/4 and Y = 2/8 which reduces to 1/4)

so H needs to be reduced by 1/4

8/4 = 2

so new coordinate is (2,2)

Answer is C