asked 32.5k views
3 votes
Start at 5 create a pattern that multiplies each no. by 3 and subtracts 2 stop when you have 5 no.

2 Answers

2 votes
For this, you'd have to multiply your starting number, which is 5 times 3 = 15

Then you would multiply what you get (15) by 3, and do this until you have 5 numbers (including 5 and 15)
answered
User Jim Ashworth
by
8.2k points
5 votes

5*3-2=13
13*3-2=37
37*3-2=109
109*3-2=325
325*3-2=973
answered
User Mark Vanzuela
by
8.8k points
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