Question

An object's position is given by x(t) = 5 + 10 t 2. what is its acceleration after 5 s

Answer 1

The acceleration after 5 seconds is 20 m/s^2.

Step-by-step explanation:

To find the acceleration, we need to take the second derivative of the position function.

x(t) = 5 + 10t^2

Taking the derivative with respect to time, we get:

v(t) = 20t

Taking the derivative again, we get the acceleration:

a(t) = 20

Therefore, the acceleration after 5 seconds is 20 m/s^2.

Answer 2

x(5)=5+10*5*2
x(5)=5+50*2
x(5)=5+100
x(5)=105