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The product of two consecutive positive even integers is 80. Find the integers

1 Answer

4 votes
Greetings!

We can create an equation for this:

(x)(x+2)=80
Distribute the Parenthesis.

x^2+2x=80
Add -80 to both sides.

(x^2+2x)+(-80)=80+(-80)

x^2+2x-80=0
Factor the Simple Trinomial.

x^2+10x-8x-80=0
Factor by Grouping.

x(x+10)-8(x+10)=0
Factor the GCF.

(x+10)(x-8)=0
The Answer Is:

(x+10)=0 \\ (x-8)=0

x=-10 \\ x=8

Either:
-10,-8 or 8,10
Can be the solution in this answer.

Hope this helps.
-Benjamin

answered
User Pradeepa
by
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