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Determine the growth defined by the equation y=3(3.4)x

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\bf \qquad \textit{Amount for Exponential Growth}\\\\ A=I(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ I=\textit{initial amount}\\ r=rate\to r\%\to (r)/(100)\\ t=\textit{elapsed time}\\ \end{cases}\\\\ -------------------------------\\\\ \stackrel{A}{y}=\stackrel{I}{3}(3.4)^(x)\implies y=3(1+\stackrel{r}{2.4})^x \\\\\\ \cfrac{r}{100}=2.4\implies r=100\cdot 2.4\implies r=\stackrel{\%}{240}
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User Anothershrubery
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5 votes

Answer:

Exponential growth.

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User Evonne
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