Question

Help! i never took this before and an answer is deeply appreciated

Answer 1

`$\frac{\sqrt[3]{x^8}}{\left(x^4\right)^(1)/(3)}=\frac{x^(8)/(3)}{x^{4\cdot(1)/(3)}}=\frac{x^{(8)/(3)}}{x^{(4)/(3)}}=x^{(8)/(3)-(4)/(3)}=x^{(8-4)/(3)}=\boxed{x^{(4)/(3)}}`

so:


`y=(4)/(3)`