Question

Right triangle ABC is shown.

a to c is 3m
c to b is a
b to a is c and ab is 50 degrees


Which equation can be used to solve for c?

sin(50o) =

sin(50o) =
cos(50o) =
cos(50o) =

Answer 1

it is A because the teacher gave me the answer hope y'all enjoy

Answer 2

The required equation which can be used to solve for the value of c is given by :

`\bf\sin 50=(3)/(c)`

Explanation:

For better understanding of the solution, see the attached figure :

AC = 3 meter

CB = a meter

BA = c meter

m∠ABC = 50°

Now, to find the value of c.

In right angle triangle right angled at C, we need to find the length of hypotenuse, so using the sine rule in the ΔABC

`\implies \sin\theta=(Perpendicular)/(Hypotenuse)\\\\\implies \sin 50=(3)/(c)`

Hence, the required equation which can be used to solve for the value of c is given by :

`\bf\sin 50=(3)/(c)`