asked 55.9k views
4 votes
Find the limit, if it exists, or type dne if it does not exist.

a. \displaystyle\lim_{(x, y) \rightarrow (0, 0)} \frac{(x + 23y)^2}{x^2 + 529y^2} =

1 Answer

4 votes

\displaystyle\lim_((x,y)\to(0,0))(\left(x+23y)^2)/(x^2+529y^2)

Suppose we choose a path along the
x-axis, so that
y=0:


\displaystyle\lim_(x\to0)(x^2)/(x^2)=\lim_(x\to0)1=1

On the other hand, let's consider an arbitrary line through the origin,
y=kx:


\displaystyle\lim_(x\to0)((x+23kx)^2)/(x^2+529(kx)^2)=\lim_(x\to0)((23k+1)^2x^2)/((529k^2+1)x^2)=\lim_(x\to0)((23k+1)^2)/(529k^2+1)=((23k+1)^2)/(529k^2+1)

The value of the limit then depends on
k, which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.
answered
User Richard G
by
8.4k points
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