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It takes 3.3 j of work to stretch a hooke's-law spring 15 cm from its unstressed length. how much the extra work is required to stretch it an additional 11.3 cm? answer in units of j.

asked
User Humbalan
by
8.4k points

1 Answer

1 vote
5.786j

Set up a proportion. Add 11.3 and 15=26.3cm.
Next, the proportion of 3.3j/15cm=×/26.3cm
answered
User Xdeepakv
by
7.9k points
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