Question

8. The population of Grand City in 1990 was 5,250. Assume the population is increasing at 2.5% per year. What was the population in Grand City in 2010 (round answer to the nearest person)?

Answer 1

20 years difference
A = P x (1 + r/100)^t
A is the end amount
P is the initial (principal) amount
r is the rate
t is the amount of time
5250 x 1.025^20=8602.736312
Rounded to nearest person is 8603 people was the population of the city in 2010.