Question

The sum of three integers is 74. The first integer is twice the second and the third is six more than the second. What are the three integers

Answer 1

let thw second integer be x
then the first = 2x
and the third integer is = 6+x
their sum = 74
x+2x+6+x = 74
4x +6 = 74
4x = 74-6 =68
x =68÷4
x = 17
then the first integer is 2×17 = 34
the third integer is 17+6 = 23

the integers are 17 , 23 and 34