Question

What is the equation of this line? y=12x−3 y=−12x−3 y=−2x−3 y=2x−3 Number graph ranging from negative 5 to 5 on both the x and y axis. A line passes through the point begin ordered pair 0 comma negative 3 end ordered pair and the point begin ordered pair 4 comma negative 1 end ordered pair

Answer 1

We are given that

A line passes through two points as

(0,-3) and (4,-1)

`(x_1,y_1)=(0,-3)`

`x_1=0,y_1=-3`

`(x_2,y_2)=(4,-1)`

`x_2=4,y_2=-1`

Firstly, we can find slope

`m=(y_2-y_1)/(x_2-x_1)`

now, we can plug values

`m=(-1+3)/(4-0)`

`m=(2)/(4)`

`m=(1)/(2)`

now, we can use point slope form of line

`y-y_1=m(x-x_1)`

we can plug values

`y+3=(1)/(2) (x-0)`

`y+3=(1)/(2)x`

`y=(1)/(2)x-3`

so, the equation of line is

`y=(1)/(2)x-3`...............Answer