21k – 3n + 9p > 3p + 12

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RITZ XAVI · Answer 1 · 2018-01-29T12:42:05+0000

solve for n.

21k−3n+9p>3p+12

Add -21k to both sides.

21k−3n+9p+−21k>3p+12+−21k

−3n+9p>−21k+3p+12

Add -9p to both sides.

−3n+9p+−9p>−21k+3p+12+−9p

−3n>−21k−6p+12

Divide both sides by -3.

−3n/−3 > −21k−6p+12/−3

n < 7k+2p−4

21k – 3n + 9p > 3p + 12

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