Question

If a glass is knocked off of a table that is 1.4 m tall, how long does it take for the glass to hit the ground?

Sorry im having so much trouble can anyone help explain what to do

Answer 1

The formula we can use in this case would be:

h = vi t + 0.5 g t^2

where h is height, vi is initial velocity = 0 since started from rest, g is gravity

Therefore calculating for t:

1.4 m = 0.5 * 9.8 m/s^2 * t^2

t^2 = 0.2857 s^2

t = 0.53 seconds