Question

Casey bought sandwiches and bags of chips. Each sandwich cost three times as much as a bag of chips. She bought 5 sandwiches for $6 each and spent $42. How many bags of chips b did she buy?

Answer 1

She bought 6 bag of chips.

Explanation:

Let the price of bag of chips be s.

Each sandwich cost three times as much as a bag of chips.

Cost of sandwich = 3s

She bought 5 sandwiches for $6.

That is cost of sandwich = 3s = 6

s = 2$

Cost of bag of chips = s = 2$

Price of 5 sandwiches = 5 x 6 = 30 $.

She spent $42, remaining money = 42 - 30 =12 $

Number of bag of chips can be bought with 12 $

`n=(12)/(2)=6`

She bought 6 bag of chips.