Question

The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, what is the partial pressure of gas c?

Answer 1

The total pressure of the mixture of the gases is calculated by adding up the products of the volume of the percentages with the pressure that is called the partial pressure of the component.

For gas C, the partial pressure can be calculated through the equation,
Partial pressure = (0.22)(4.1 atm)
partial pressure = 0.902 atm

ANSWER: 0.902 atm

Answer 2

The partial pressure of gas C is 0.902 atm

calculation

partial pressure of gas c =[( percent by volume of gas C / total percent) x total pressure]

percent by volume of gas C= 22%

Total percent = 36% +42% + 22% = 100 %

Total pressure = 4.1 atm

partial pressure of gas C is therefore = 22/100 x 4.1 atm = 0.902 atm