Question

How do I solve for r in the following equation?
r+3/r=-4

Answer 1

I don't understand exactly what you mean, so there are two options

1.

`\displaystyle (r+3)/(r) =-4\\\\r+3=-4r\\\\3=-5r\\\\r=- (3)/(5)`

2.

`\displaystyle r+(3)/(r) =-4\\\\r^2 +3=-4r\\\\r^2+4r+3=0\\\\r_(1,2)= (-4\pm √(16-12) )/(2)= (-4\pm 2)/(2) =(-3), (-1)`