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(3a x3 -5bx3) + -------ax3 + -----------bx3 = (ax3 + bx3).

(3a x3 -5bx3) + -------ax3 + -----------bx3 = (ax3 + bx3).
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(3a x3 -5bx3) + -------ax3 + -----------bx3 = (ax3 + bx3).

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User EnikiBeniki
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2 Answers

2 votes
can you make this a little more clear?
answered
User Lulzim Fazlija
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7 votes
3a x3 ax ax3 (ax47) 12 5 ca
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User Asiviero
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