Question

write an equation of the circle that is tangent to both axes with radius sqrt5 and center in quadrant 3

Answer 1

check the picture below.


`\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 ~~ \begin{array}{lllll} center~(&\quad {{ h}},&\quad {{ k}}\quad )\qquad radius=&{{ r}}\\ &-√(5)&-√(5)&√(5) \end{array} \\\\\\\ [x-(-√(5))]^2+[y-(-√(5))]^2=(√(5))^2 \\\\\\ (x+√(5))^2+(y+√(5))^2=5`