asked 164k views
3 votes
How much energy is required to heat 32.5 g of water from 34°C to 75°C

asked
User Nighil
by
8.0k points

1 Answer

2 votes
Q = mc (delta T) = 32.5 x 1 x (75-34) = 1332.5 cal
answered
User Giraff
by
8.6k points
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