asked 9.4k views
3 votes
What is the area of a triangle whose vertices are

R(−4, 2),S(1, 2), and T(−5, −4)?
 
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asked
User Babu R
by
7.3k points

2 Answers

5 votes

Answer:

15 units

Explanation:

I took the test.

answered
User Aravindh S
by
7.9k points
1 vote
ANSWER

15 square units.

EXPLANATION

This triangle has one of its height(altitudes) falling outside the triangle.

We determine the base using absolute value method. This is because the coordinates of
R(-4,2) and
S(1,2) tell us that this line is horizontal. The y-values are constant.

Therefore
|RS|=|1--4|


\Rightarrow |RS|=|1+4|


\Rightarrow |RS|=|5|


\Rightarrow |RS|=5

Also

The triangle is bounded between
y=2 and
y=-4.

Therefore the vertical height of interest,


|RT|=|-4-2|


|RT|=|-6|


|RT|=6

We can now find the area using the formula


Area=(1)/(2)base* height


Area=(1)/(2)*6 * 5


Area=3 * 5


Area=15 square units
What is the area of a triangle whose vertices are R(−4, 2),S(1, 2), and T(−5, −4)? Enter-example-1
answered
User HerberthObregon
by
8.9k points

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